Processing math: 100%

Problem #44

Power Sum

Let k = 4128^6 + 6^{4128}.

What is \sum_{n=1}^{17040384}(units digit of k^n + n^k)?

Contributed by Satyam Vijay

Solved by 389 users

Log in to submit answers.

Is something wrong?

Maintaining a collection of high quality questions is our top priority. If, however, you do find an error, report the problem and we'll make sure it is reviewed soon.