Let $f ( n ) = \sum_{ d | n } \mu ( d ) h ( n / d )$ where $h ( x ) =$ Sum of divisors of $x$

$g ( n ) = \sum_{ d | n } \mu ( d ) f ( n / d )$

Find $S=\sum_{ n = 1 }^{10000000000} g ( n )$ modulo $2^{64}$

Note: here $\mu ( n )$ is Mobius Function.