Let $x$ = last 7 non-zero digit of $99 ^ {99}!$

Define $F(n,k)$ = Sum of kth powers of all divisors of $n$, so for example $F(6,2) = 1^2 + 2^2 + 3^2 + 6^2 = 50$

Define further $G(a,b,k)$ as: Sum of $F(j,k)$ where $j$ varies from $a$ to $b$ both inclusive

You need to enter the value of $G(1,x*x,2)$ modulo $(10^9+7)$