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Problem #106

Back Propagate

Let the initial terms of a sequence be {1, 1, 1, 1, 2, 11, 84, 676, 5477, 44407}.

Propagate this sequence backwards to produce 20 new terms. Find the sum of these 20 terms (written in simplest fraction form as p/q ). What is the value of (p*q) \mod (10^9+7)?

dp

Contributed by Jay Hitesh Bosamiya

Solved by 26 users

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